Write a program that checks whether two matrices are equal or not.
Difficulty level
This exercise is mostly suitable for students
#include <stdio.h>
#include <conio.h>
#define SIZE 50
void main()
{
int A[SIZE][SIZE];
int B[SIZE][SIZE];
int R, C; /* dimensions */
int I, J;
do {
printf("Number of rows (max.%d) : ", SIZE);
scanf("%d", &R);
} while (R <= 0 || R > SIZE);
do {
printf("Number of columns (max.%d) : ", SIZE);
scanf("%d", &C);
} while (C <= 0 || C > SIZE);
printf("*** Matrix A ***\n");
for (I = 0; I<R; I++)
for (J = 0; J<C; J++)
{
printf("A[%d][%d] : ", I, J);
scanf("%d", &A[I][J]);
}
printf("*** Matrix B ***\n");
for (I = 0; I<R; I++)
for (J = 0; J<C; J++)
{
printf("B[%d][%d] : ", I, J);
scanf("%d", &B[I][J]);
}
printf("Matrix A :\n");
for (I = 0; I<R; I++)
{
for (J = 0; J<C; J++)
printf("%6d", A[I][J]);
printf("\n");
}
printf("Matrix B :\n");
for (I = 0; I<R; I++)
{
for (J = 0; J<C; J++)
printf("%6d", B[I][J]);
printf("\n");
}
for (I = 0; I<R; I++)
{
for (J = 0; J<C; J++)
// if the corresponding entries of matrices are not equal, break
if(A[I][J]!=B[I][J])
break;
//once here, 2 cases:
// 1. J==C, we have looped over J and we exit normally, nothing to do
// 2. J<C, we exit from break, so we need to exit the outer loop too
if(J<C)
break;
}
if(J<C)
printf("A is not equal to B");
else
printf("A is equal to B");
getch();
}
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