Given that \( \log_{10}4 = 0.6020 \) and \( \log_{10}5 = 0.6989 \) , find the value of \( \log_{20}10 \).
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This exercise is mostly suitable for students
We recollect that log(xy) = log(x)+log(y).
Therefore, using log_{10}4 = 0.6020 and log_{10}5 = 0.6989, we can calculate log_{10}20= 0.6020 + 0.6989 = 1.3009
Further, we note that log_{b}a log_{a}b = 1.
Therefore, log_{20}10= 1/1.3009 = 0.7686.Back to the list of exercises
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