Write a program that reads two integer values (A and B) from the keyboard and displays the sign of the sum of A and B without performing the addition.

Use the fabs function from the <math.h> library.

#include<stdio.h>
#include <math.h>
int main()
{
	int A, B;
 	printf("Enter 2 integers :");
 	scanf("%i %i", &A, &B);

 	if ((A>0 && B>0) || (A<0 && B>0 && fabs(A)<fabs(B)) 
                  || (A>0 && B<0 && fabs(A)>fabs(B)))
    		printf("The sign of the sum %i + %i is positive\n",A,B);
 	else if ((A<0 && B<0) || (A<0 && B>0 && fabs(A)>fabs(B)) 
                       || (A>0 && B<0 && fabs(A)<fabs(B)))
   		 printf("The sign of the sum %i + %i is negative\n",A,B);
 	else
    		printf("The sum %i + %i is zero\n", A, B);

	return 0;
}


The above solution doesn't work correctly when one of the integers is 0.

Corrected version provided by Hadi Mazloum
#include<stdio.h>
#include <math.h>
int main()
{
	int A, B;
 	printf("Enter 2 integers :");
 	scanf("%i %i", &A, &B);

 	if ((A>0 && B>0) || (A<=0 && B>0 && fabs(A)<fabs(B)) 
                  || (A>0 && B<=0 && fabs(A)>fabs(B)))
    		printf("The sign of the sum %i + %i is positive\n",A,B);
 	else if ((A<0 && B<0) || (A<0 && B>=0 && fabs(A)>fabs(B)) 
                       || (A>=0 && B<0 && fabs(A)<fabs(B)))
   		 printf("The sign of the sum %i + %i is negative\n",A,B);
 	else
    		printf("The sum %i + %i is zero\n", A, B);

    return 0;
}