\(\begin{array}{ccccc}3&3&3&3&3\\3&2&2&2&3\\3&2&1&2&3\\3&2&2&2&3\\3&3&3&3&3\end{array}\) 

Write a program that reads a number and displays the above pattern.

In order to solve this pattern, you need to subdivide it into 2 parts i.e. an upper part and a lower part. Again each part should be subdivided into 3 parts i.e. a left part (red), a middle part (green) and a right part (blue).

\(\begin{array}{ccccccc}{\color{green} 4}&{\color{green} 4}&{\color{green} 4}&{\color{green} 4}&{\color{green} 4}&{\color{green} 4}&{\color{green} 4}\\{\color{red} 4}&{\color{green} 3}&{\color{green} 3}&{\color{green} 3}&{\color{green} 3}&{\color{green} 3}&{\color{blue} 4}\\{\color{red} 4}&{\color{red} 3}&{\color{green} 2}&{\color{green} 2}&{\color{green} 2}&{\color{blue} 3}&{\color{blue} 4}\\{\color{red} 4}&{\color{red} 3}&{\color{red} 2}&{\color{green} 1}&{\color{blue} 2}&{\color{blue} 3}&{\color{blue} 4}\\&&&&&&\\{\color{red} 4}&{\color{red} 3}&{\color{red} 2}&{\color{green} 2}&{\color{blue} 2}&{\color{blue} 3}&{\color{blue} 4}\\{\color{red} 4}&{\color{red} 3}&{\color{green} 3}&{\color{green} 3}&{\color{green} 3}&{\color{blue} 3}&{\color{blue} 4}\\{\color{red} 4}&{\color{green} 4}&{\color{green} 4}&{\color{green} 4}&{\color{green} 4}&{\color{green} 4}&{\color{blue} 4}\end{array}\) 

#include<stdio.h>
#include<conio.h>

void main()
{
	int N, i, j;
	do{
		printf("Enter N: ");
		scanf("%d",&N);
	}while(N<=0);

	// for the pper half
    	for(i=N; i>=1; i--)
    	{
        	// left part
        	for(j=N; j>i; j--)
            		printf("%d", j);

        	// middle part
        	for(j=1; j<=(i*2-1); j++)
            		printf("%d", i);

        	// right part
        	for(j=i+1; j<=N; j++)
            		printf("%d", j);

        	printf("\n");
    	}

    	// for the lower half
    	for(i=1; i<N; i++)
    	{
        	// left part
        	for(j=N; j>i; j--)
            		printf("%d", j);

        	// middle part
        	for(j=1; j<=(i*2-1); j++)
            		printf("%d", i+1);

        	// right part
        	for(j=i+1; j<=N; j++)
            		printf("%d", j);

        	printf("\n");
    	}

	getch();
}